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Q131. - (Topic 3) 

Identify the four valid IPv6 addresses. (Choose four.) 

A. :: 

B. ::192:168:0:1 

C. 2000:: 

D. 2001:3452:4952:2837:: 

E. 2002:c0a8:101::42 

F. 2003:dead:beef:4dad:23:46:bb:101 

Answer: A,B,E,F 

Explanation: 

http://www.intermapper.com/ipv6validator http://www.ripe.net/lir-services/new-lir/ipv6_reference_card.pdf 


Q132. - (Topic 5) 

Refer to the exhibit. 

A problem with network connectivity has been observed. It is suspected that the cable connected to switch port Fa0/9 on Switch1 is disconnected. What would be an effect of this cable being disconnected? 

A. Host B would not be able to access the server in VLAN9 until the cable is reconnected. 

B. Communication between VLAN3 and the other VLANs would be disabled. 

C. The transfer of files from Host B to the server in VLAN9 would be significantly slower. 

D. For less than a minute, Host B would not be able to access the server in VLAN9. Then normal network function would resume. 

Answer:

Explanation: 

Because Switch1 has multiple redundant links in this network, traffic would not work for less than a minute, and then it would get rerouted along the longer path to the host. The 1 minute outage would be the length of time it takes STP to converge. 


Q133. - (Topic 3) 

OSPF is configured using default classful addressing. With all routers and interfaces operational, how many networks will be in the routing table of R1 that are indicated to be learned by OSPF? 

A. 2 

B. 3 

C. 4 

D. 5 

E. 6 

F. 7 

Answer:

Explanation: 

Although OSPF is configured using default classful addressing but OSPF is a link-state routing protocol so it will always send the subnet mask of each network in their advertised routes. Therefore R1 will learn the the complete subnets. Four networks list below will be in the routing table of R1:+ 172.16.2.64/30+ 172.16.2.228/30+ 172.16.2.232/30+ 172.16.3.0/24 Note: Other networks will be learned as “Directly connected” networks (marked with letter “C”) 


Q134. - (Topic 3) 

Given an IP address of 192.168.1.42 255.255.255.248, what is the subnet address? 

A. 192.168.1.8/29 

B. 192.168.1.32/27 

C. 192.168.1.40/29 

D. 192.168.1.16/28 

E. 192.168.1.48/29 

Answer:

Explanation: 

248 mask uses 5 bits (1111 1000) 

42 IP in binary is (0010 1010) 

The base subnet therefore is the lowest binary value that can be written without changing 

the output of an AND operation of the subnet mask and IP... 

1111 1000 AND 

0010 1010 equals 

0010 1000 - which is .40 

/24 is standard class C mask. 

Adding the 5 bits from the .248 mask gives /29 


Q135. - (Topic 3) 

R1 is configured with the default configuration of OSPF. From the following list of IP addresses configured on R1, which address will the OSPF process select as the router ID? 

A. 192.168.0.1 

B. 172.16.1.1 

C. 172.16.2.1 

D. 172.16.2.225 

Answer:

Explanation: 

The Router ID (RID) is an IP address used to identify the router and is chosen using the following sequencE. 

+

 The highest IP address assigned to a loopback (logical) interface. + If a loopback interface is not defined, the highest IP address of all active router's physical interfaces will be chosen. 

+

 The router ID can be manually assigned In this case, because a loopback interface is not configured so the highest active IP address 192.168.0.1 is chosen as the router ID. 


Q136. - (Topic 7) 

Which function enables an administrator to route multiple VLANs on a router? 

A. IEEE 802 1X 

B. HSRP 

C. port channel 

D. router on a stick 

Answer:


Q137. - (Topic 4) 

Refer to the exhibit. 

A company wants to use NAT in the network shown. Which commands will apply the NAT configuration to the proper interfaces? (Choose two.) 

A. R1(config)# interface serial0/1 R1(config-if)# ip nat inside 

B. R1(config)# interface serial0/1 R1(config-if)# ip nat outside 

C. R1(config)# interface fastethernet0/0 R1(config-if)# ip nat inside 

D. R1(config)# interface fastethernet0/0 R1(config-if)# ip nat outside 

E. R1(config)# interface serial0/1 R1(config-if)# ip nat outside source pool 200.2.2.18 255.255.255.252 

F. R1(config)# interface fastethernet0/0 R1(config-if)# ip nat inside source 10.10.0.0 255.255.255.0 

Answer: B,C 

Explanation: 

For NAT, you need to define which interfaces are inside and which are outside. The outside interface is the one that connects to the external network, and the one that will be used for translating addresses. The inside interface is for the internal network, and defines the network IP addresses that will get translated to the one specified in the outside network. 


Q138. - (Topic 3) 

What two things does a router do when it forwards a packet? (Choose two.) 

A. switches the packet to the appropriate outgoing interfaces 

B. computes the destination host address 

C. determines the next hop on the path 

D. updates the destination IP address 

E. forwards ARP requests 

Answer: A,C 

Explanation: 

A primary function of a router is to forward packets toward their destination. This is accomplished by using a switching function, which is the process used by a router to accept a packet on one interface and forward it out of another interface. A key responsibility of the switching function is to encapsulate packets in the appropriate data link frame type for the outgoing data link and determining the next hop device to send the frame to. 


Q139. - (Topic 1) 

Refer to the exhibit. 

HostX is transferring a file to the FTP server. Point A represents the frame as it goes toward the Toronto router. What will the Layer 2 destination address be at this point? 

A. abcd.1123.0045 

B. 192.168.7.17 

C. aabb.5555.2222 

D. 192.168.1.1 

E. abcd.2246.0035 

Answer:

Explanation: 

For packets destined to a host on another IP network, the destination MAC address will be the LAN interface of the router. Since the FTP server lies on a different network, the host will know to send the frame to its default gateway, which is Toronto. 


Q140. - (Topic 3) 

Refer to the exhibit. 

When running OSPF, what would cause router A not to form an adjacency with router B? 

A. The loopback addresses are on different subnets. 

B. The values of the dead timers on the routers are different. 

C. Route summarization is enabled on both routers. 

D. The process identifier on router A is different than the process identifier on router B. 

Answer:

Explanation: 

To form an adjacency (become neighbor), router A & B must have the same Hello interval, Dead interval and AREA numbers